 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  5 equilaterals (Posted on 2021-09-10) A, B, C, D, E, F, G are points in order along the circumference of a circle.

W, X, Y, Z are points in order along chord AG.

ABW, WCX, XDY, YEZ, ZFG are equilateral triangles.

If AB=1, find the side lengths of the other four triangles.

 No Solution Yet Submitted by Jer Rating: 5.0000 (2 votes) Comments: ( Back to comment list | You must be logged in to post comments.) re: solution(s) --- Correction! | Comment 2 of 7 | (In reply to solution(s) by Charlie)

The unique solution is in fact symmetrical. I had neglected to subract  the initial x in the linear equation formulae.

clc
A=[0 0]; B=[1/2 sqrt(3)/2];
W=[1 0];

ratio1=3.6855439326708

X=[1+ratio1 0];
C=(W+X)/2 + [0 ratio1*sqrt(3)/2];

Pt1=(A+B)/2; Pt2=(B+C)/2;
m1=(B(1)-A(1))/(A(2)-B(2));
m2=(C(1)-B(1))/(B(2)-C(2));

syms x y
x1=Pt1(1); y1=Pt1(2);
Eq1=y==y1+m1*(x-x1);   % corrected line (subtract x1)
x2=Pt2(1); y2=Pt2(2);
Eq2=y==y2+m2*(x-x2);   % corrected line (subtract x2)

solve([Eq1 Eq2],[x y]);
ctr=eval([ans.x ans.y]);
ctrx=ctr(1); ctry=ctr(2);

B
C
X
start=X(1);
Eq2=x==start+y/sqrt(3);
solve([Eq1 Eq2],[x y]);
D=eval([ans.x ans.y]);
D=D(2,:)
Y=[D(1)*2-start 0]

start=Y(1);
Eq2=x==start+y/sqrt(3);
solve([Eq1 Eq2],[x y]);
E=eval([ans.x ans.y]);
E=E(2,:)
Z=[E(1)*2-start 0]

start=Z(1);
Eq2=x==start+y/sqrt(3);
solve([Eq1 Eq2],[x y]);
F=eval([ans.x ans.y]);
F=F(2,:)
G=[F(1)*2-start 0]
disp([ratio1 G(1)-2*ctrx])

`                       center of circle                  x                        y                      radiusratio1 =           3.6855439326708          7.29161703982328         -3.63246679158001          8.14631782140697B =                       0.5         0.866025403784439C =           2.8427719663354          3.19177467245652X =           4.6855439326708                         0D =          7.29161703982327          4.51385102982696Y =          9.89769014697573                         0E =          11.7404621133111          3.19177467245653Z =          13.5832340796465                         0F =          14.0832340796465         0.866025403784447G =          14.5832340796466                         0           3.6855439326708                         0>> `

3.6855439326708 is the size of each side of WCX and of XDY is 9.89769014697573  -  4.6855439326708  = 5.21214621430493, which is the largest, central, triangle. The remaining two are mirror images of the first two.

The whole chord is 14.5832340796466 units long.

The center of the circle, when the horizontal chord begins at the origin, is at  (7.29161703982328, -3.63246679158001) and its radius is  8.14631782140697, so the chord is not quite the diameter.

 Posted by Charlie on 2021-09-12 12:03:37 Please log in:

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