All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
A permutation puzzle 2 (Posted on 2022-05-21) Difficulty: 3 of 5
Each of M, N and P is a 4 digit non-leading zero positive integer such that:
  1. M+N=P
  2. The digits of each of M,N and P are distinct.
  3. Each of M, N and P are permutations of one another.
Determine all possible triplets (M,N,P).

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
No SubjectK Sengupta2022-08-02 10:01:51
Analytical NoteSteve Herman2022-05-22 07:53:01
SolutionComputer solutionLarry2022-05-21 09:11:45
 Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:

blackjack

flooble's webmaster puzzle

Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information