All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Cubic Diophantine Conclusion II (Posted on 2022-08-13) Difficulty: 3 of 5
Each of A, B and C is a positive integer, with A less than B, that satisfies this equation:
                A3+B3=19C3
Determine all triplets (A,B,C) with A+B+C under 100,000

*** As an extra challenge only, solve this puzzle without using a computer program/spreadsheet aided method.

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
some thoughtsbroll2022-08-14 03:27:23
Solutioncomputer solutionCharlie2022-08-13 11:41:12
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information