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Cubic Diophantine Conclusion II (Posted on 2022-08-13) Difficulty: 3 of 5
Each of A, B and C is a positive integer, with A less than B, that satisfies this equation:
                A3+B3=19C3
Determine all triplets (A,B,C) with A+B+C under 100,000

*** As an extra challenge only, solve this puzzle without using a computer program/spreadsheet aided method.

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
some thoughtsbroll2022-08-14 03:27:23
Solutioncomputer solutionCharlie2022-08-13 11:41:12
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