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Year Yearn 4 (Posted on 2022-12-18) Difficulty: 3 of 5
Determine all possible triplets (x,y,n) of positive integers, with n>1, that satisfy this equation:
                 xn - yn = 2015

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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Some Thoughts computer findings | Comment 1 of 5
 clearvars,clc
  for n=2:25
    for y=1:100000
      x=(y^n+2015)^(1/n);
      if abs(x-round(x))<.0000000000001
        if x^n-y^n==2015
        disp([x y n]);
        end
      end
    end
 end
 
 finds only
 
     x     y      n
 
     48    17     2
     84    71     2
    204   199     2
   1008  1007     2

   

  Posted by Charlie on 2022-12-18 10:28:52
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