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Arithmetic Sequence Crossed Integer Determination Puzzle (Posted on 2023-02-12) Difficulty: 3 of 5
+----+----+----+----+
| 23 |    |    |    | 
+----+----+----+----+
|    |    | 64 |    |
+----+----+----+----+
|    |  N |    |    | 
+----+----+----+----+
|    |    |    |101 |  
+----+----+----+----+
In the 4x4 grid provided above:
  • Each the 16 values appearing in the 16 cells is a positive integer.
  • The 4 values corresponding to each of the 4 rows are in arithmetic sequence.
  • The 4 values corresponding to each of the 4 columns are in arithmetic sequence.
Determine the total number of distinct positive integer values that N can assume.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Counting analytically | Comment 5 of 6 |
(In reply to Solution by Larry)

Using Larry's notation, we want to count the number of solutions.

All numbers need to be positive, but it is sufficient for all corners to be positive.  In other words, we need H and Q to both be positive.

H = 23 + 3a, so 23 + 3a > 0, or a > -7.666

As for Q, we can calculate it as follows:
   G= 23 + 2a   and   K = 64
Because this is an arithmetic sequence, 
   S = G + 3*(K-G) = 146 - 4a

Then Q = 101 + 3*(S-101) = 236 - 12a
   Q > 0 if a < 236/12 = 19.666

-7.666 < a < 19.666 means that there are 27 valid integer values of a, and that is our answer.


Edited on February 13, 2023, 9:24 am
  Posted by Steve Herman on 2023-02-12 19:30:05

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