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From sum to addends 2 (Posted on 2022-07-28) Difficulty: 3 of 5
Begin with an N-digit positive integer (no leading zero) and from it create N more integers (each N-1 digits long) by sequentially removing the units digit, or the tens digit, etc from the original number.
The sum of these N+1 integers is the final result.

For example, 1234 + 123 + 124 + 134 + 234 = 1849

1) What original number yields 2022 as the result?
2) How about 487929?
3) If the original number is represented by the concatenation of digits "dN-1 dN-2 ... d2 d1 d0", provide an algebraic formula for the final result.

The formula in 3) should be a function of N, i, and the di:
where the di are the individual digits, and i is the position of the digit.
Note that I am representing the ones digit as i=0.

No Solution Yet Submitted by Larry    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
computer solutionCharlie2022-07-28 11:40:05
SolutionJer2022-07-28 09:21:32
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