The sum of these N+1 integers is the final result.

For example, 1234 + 123 + 124 + 134 + 234 = 1849

1) What original number yields 2022 as the result?

2) How about 487929?

3) If the original number is represented by the concatenation of digits "d_{N-1} d_{N-2} ... d_{2} d_{1} d_{0}", provide an algebraic formula for the final result.

The formula in 3) should be a function of N, i, and the d_{i}:

where the d_{i} are the individual digits, and i is the position of the digit.

Note that I am representing the ones digit as i=0.