All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Cryptarithm Crossed Integer Constant Illation (Posted on 2023-04-22) Difficulty: 3 of 5
Each of a, b, and c is a different base ten digit and n is a positive integer such that:

ab2+c2=ac2+cb2=n
For example:
272+12=212+172=730

Determine the total number of values of the positive integer constant n less than 2023, such that we will have valid values of a,b, and c satisfying the abovementioned condition.

***** No number can contain any leading zero.

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (2 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: SolutionMath Man2023-05-06 20:35:48
SolutionSolutionBrian Smith2023-04-22 13:59:50
Hints/Tips"ab" means 'a' concatenated with 'b'Larry2023-04-22 09:44:17
Some Thoughts45 other solutionsSteve Herman2023-04-22 07:34:23
SolutionComputer solutionLarry2023-04-22 06:40:44
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information