• P is a convex, near regular 2023sided polygon.
• Precisely 2022 of its sides have length 1, but the remaining side has a length different from 1.
Determine the maximum area of the polygon.
Probably a half circle; so the diameter would be the 2023rd side should be 4044/pi
More accurately, figure 1/2 the area of a totally regular polygon of 4044 sides
Regular poly of n equal sides and side length s:
Area = n*s^2 /(4* tan(pi/n))
Area of 4044gon with s=1: 1301404.61490485
Half of that is 650702.307452425 (assumed maximum area for the 2023 sided polygon)
The "diameter" is twice the "radius": sin(pi/n) = (s/2)/radius
radius = (s/2)/sin(pi/n)
radius = s/(2*sin(pi/n))
2*radius = 2023rd side length = 1/(sin(pi/n)) = 1287.24530920272 ****
which is pretty close to 4044/pi = 1287.24517972725
But this is not a proof or an optimization

Posted by Larry
on 20230530 13:46:07 