All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Pandigital Crossed Perfect Square Poser (Posted on 2023-06-08) Difficulty: 3 of 5
Two (non leading zero) five digit positive integers A and B together uses the digits 0 to 9 exactly once, with B=3*A

What are A and B, if the concatenated form of the first three digits of B is a perfect square?

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution computer solution | Comment 1 of 2
clearvars,clc
digs='0123456789';
prm=combinator(10,5,'p');
As=digs(prm);
for i=1:length(As)
  A=As(i,:);
  B=char(string(3*str2double(A)));
  AB=[A B];
  if isequal(sort(AB),unique(AB))
    sq=str2double(B(1:3));
    sr=sqrt(sq);
    if sr==round(sr)
      disp([A ' ' B])
    end
  end
end

finds

32058  96174

where the latter is 3 times the former and 961 = 31^2.

  Posted by Charlie on 2023-06-08 12:02:15
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (10)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information