We know that 2025 = 45
2. Therefore, 2025 is a perfect square in base ten.
Determine all positive integer value of N greater than 3, for which 2013 base N is a perfect square.
Provide valid reasoning for your answer.
2013 in
base 6 is 441 which is 21^2
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big = 1000
sqroot = int((2*big**3 + big + 3)**.5)
squares = [i*i for i in range(sqroot + 1)]
for x in range(big):
if 2*x**3 + x + 3 in squares:
print(x, 2*x**3 + x + 3, int((2*x**3 + x + 3)**.5))
OUTPUT: 6 441 21
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Posted by Larry
on 2023-06-26 11:49:15 |
solution
