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Digits of N^6 (Posted on 2023-10-11) Difficulty: 3 of 5
Find a positive integer N such that the digits of N combined with the digits of N^2 and the digits of N^3 are exactly the digits of N^6.

Extra credit: Find additional solutions, other than multiples of 10.

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
n = 9305649
n^2 = 86595103311201
n^3 = 805823636532774274449
n^6 = 649351733194904702291358580642658374253601

n = 71032113
n^2 = 5045561077244769
n^3 = 358396864587252160266897
n^6 = 128448312545973161578627675360153279566274008609

n = 97560675
n^2 = 9518085306455625
n^3 = 928590827205392632546875
n^6 = 862280924369995358075005678535785615549072265625

For an explanation, refer to the solution submitted by Larry here and here.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Some ThoughtsD'oh; I forgot to post my solutions, here they areLarry2023-10-11 14:21:54
re: Computer solutionCharlie2023-10-11 10:28:43
SolutionComputer solutionLarry2023-10-11 08:57:37
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