6 football teams each of different level
of play compete in a knockout fashion: the 1st pair chosen at random and in the following rounds the winner is facing another randomly chosen team.
Given that a certain team won three games so-far what is
the probability of winning the 4th game?
(In reply to
an ambiguity? by Steven Lord)
Three games so far : no ambiguity
If you want to assume first - be my guest and solve another version or both
However, I am ready to post some clarifications, even if they are unneeded to exclude misunderstandings
Please read them carefully and comply.
re: an ambiguity? @St. Lord
