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52-card lottery (Posted on 2023-03-29) Difficulty: 3 of 5

Let a 52 deck of numbered cards be created as follows:

2 special cards: 0 and 1
25 powers of 2: 2, 4, 8, ..., 2^25
25 powers of 3: 3, 9, 27, ..., 3^25

Shuffle the deck and draw at random 3 cards. Evaluate the product of the 3 numbers, say P.

What is the probability of P=0?
What is the probability of P being a non zero integer square?
What is the probability of P being a 4-digit number?

No Solution Yet Submitted by Ady TZIDON    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: Part 1 and 2 solutions | Comment 10 of 11 |
(In reply to Part 1 and 2 solutions by Brian Smith)

This agrees with my computer total.


Initially I was worrying that the test for being a square was being overwhelmed by numbers larger than could be handled by the square root function losing the extended precision, but then I substituted smaller odd and even powers in the deck, WLOG:

'0  1  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3  4  9  2  3'

and still came out with 6200 cases.

  Posted by Charlie on 2023-03-29 10:52:26
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