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Matchstick Frenzy (Posted on 2002-06-27) Difficulty: 3 of 5
A heap of 48 matches are divided into three groups.

If I take as many matches from the first group as there are in the second group and add them to the second, and then take as many from the second group as there are in the third group and add them to the third, and finally take as many from the third group as there are in the first group and add them to the first group, the number of matches in each heap would be equal.

How many matches were in the three groups originally?

See The Solution Submitted by Dulanjana    
Rating: 3.7692 (13 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
answer | Comment 5 of 6 |
The first group had 22 matches, the second group had 14 matches and the third group had 12 matches.
  Posted by K Sengupta on 2008-03-09 12:27:55
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