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Numbers in pi 2 (Posted on 2023-11-05) Difficulty: 3 of 5
What is the first 12-digit sequence in the duodecimal expansion of pi that contains each digit exactly once?

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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soln | Comment 1 of 7
I grabbing a big (1 M digit) Pi text file, and  
used the easy "on the fly" method of conversion...
                             3.
0.1415926 × 12 = 0.6991112 + 1
0.6991112 × 12 = 0.3893344 + 8
0.3893344 × 12 = 0.6720128 + 4
0.6720128 × 12 = 0.0641536 + 8
which just involved multiplying the huge numbers by 12. 

I wondered how many digits I would need to look through, so I computed 
1/Prob(of success) = 12^11/11! since the likelihood of the next digit not
being a repeat is 11/12 x 10/12 ... 1/12. This gave 18613. So, I decided to 
look through the 1st 30,000 digits. The solution happily showed up towards the end.
The program is here.  First, as a check, I list the 1st 5 and last 5 digits of Pi
out of a million in base 10. I also list the first few digits of Pi base 12 = 3.1848093b9... 
as a check. The program runs in a minute. 
lord@rabbit 13324 % p12
14159
62541
Pi(base 12)  = 3 .  1  8  4  8  0  9  4  9  3 11  9  1  8  6  6  4  5  7  3 10

 1000 out of 30000
 2000 out of 30000
 4000 out of 30000
 5000 out of 30000
.
.
.

26000 out of 30000
27000 out of 30000
28000 out of 30000

digit  value
index  base 12
---------------
 28641  1
 28642 11
 28643  2
 28644  5
 28645  0
 28646  7
 28647  3
 28648  6
 28649  9
 28650 10
 28651  8
 28652  4
lord@rabbit 13324 % prob (inverted) 
   18613.9238    
  

Edited on November 6, 2023, 10:36 am
  Posted by Steven Lord on 2023-11-06 09:01:43

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