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Linear Cubes (Posted on 2003-12-19) Difficulty: 4 of 5
In the following table, each row of P, Q, and R are a set of numbers for which
P³ + Q³ + R³ = P_Q_R
where P_Q_R is composed of the digits of P, Q, and R put together.
For example, 4³ + 18³ + 33³ = 41833.

In this puzzle, however, P, Q, and R are each two digit numbers.
Also, there are no zeroes in any of the variables.

     P        Q        R    
     a        k        j
    a/2      c/4       n
     b        c    2(h+j/4)/a
    j/4      2g/7     3a/4
     2m       f       e/31
     2m      j/2      d/37

The grid below contains all the variables in the table, where a1 is the first digit of a, a2 is the second digit of a, etc, and where a1 and b1 (being in the same box of the grid) are the same digit.

 ___________________
| a1 | a2 | c1 | c2 |
| b1 |    | d1 | f1 |
|----|----|----|----|
| e1 | e2 | e3 |    |
| b2 | h1 | d2 | f2 |
|----|----|----|----|
|    | g1 | g2 | g3 |
| k1 | h2 | d3 | n1 |
|----|----|----|----|
| j1 | j2 | m1 | m2 |
| k2 | h3 |    | n2 |
 ŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻ
Complete the grid from the given information.

  Submitted by DJ    
Rating: 4.2000 (5 votes)
Solution: (Hide)

4 4 7 2
8 3 7 8
4 1 7 5
6 4 4 9
The first step is to determine the possible values of P, Q, and R. I used the following javascript:
for (var p=10; p<100; p++) {
  for (var q=10; q<100; q++) {
    for (var r=10; r<100; r++) {
      var total=Math.pow(p,3)+Math.pow(q,3)+Math.pow(r,3);
      var result=p*10000+q*100+r;
      if (total==result) {
        document.write(p + "³ + ");
        document.write(q + "³ + ");
        document.write(r + "³ = ");
        document.write(result + "<br>");
      }
    }
  }
}
to come up with:
16³ + 50³ + 33³ = 165033
22³ + 18³ + 59³ = 221859
34³ + 10³ + 67³ = 341067
44³ + 46³ + 64³ = 444664
48³ + 72³ + 15³ = 487215
98³ + 28³ + 27³ = 982827
98³ + 32³ + 21³ = 983221
Then, looking at the table, we see that two of the P-values are a and a/2. These, therefore, must be 44 and 22. The first two rows, then, must correspond to 44³+46³+64³=444664 and 22³+18³+59³=221859, respectively. That gives us:
a = 44    g = 
b =       h = 
c = 72    j = 64
d =       k = 46
e =       m = 
f =       n = 59

4 4 7 2
· · · ·
4 · · 5
6 4 · 9
From the determined values of a and j, the fourth row corresponds to 16³+50³+33³=165033, and g=175:
a = 44    g = 175
b =       h = 
c = 72    j = 64
d =       k = 46
e =       m = 
f =       n = 59

4 4 7 2
· · · ·
4 1 7 5
6 4 · 9
Also, we see that 2m is used twice as a P-value. Therefore, 2m must equal 98, and m=49. Also, the last row has Q=j/2, which we already know is 32 (j=64). Therefore, the last two rows are 98³+28³+27³=982827 and 98³+32³+21³=983221, respectively, and we are able to determine d, e, and f:
a = 44    g = 
b =       h = 
c = 72    j = 64
d =       k = 46
e =       m = 
f =       n = 59

4 4 7 2
· · · ·
4 · · 5
6 4 · 9
From the determined values of a and j, the fourth row corresponds to 16³+50³+33³=165033, and g=175:
a = 44    g = 175
b =       h = 
c = 72    j = 64
d = 777   k = 46
e = 837   m = 49
f = 28    n = 59

4 4 7 2
8 3 7 8
4 1 7 5
6 4 4 9
From the completed squares in the grid, now, we have all the values. They are:
a = 44    g = 175
b = 48    h = 314
c = 72    j = 64
d = 777   k = 46
e = 837   m = 49
f = 28    n = 59
The sets of (P, Q, R) in the table are, in order:
(44, 46, 64)
(22, 18, 59)
(48, 72, 15)
(16, 50, 33)
(98, 28, 27)
(98, 32, 21)

Original puzzle by John Gowland

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: SOLUTIONSilverKnight2003-12-19 11:14:32
SolutionSOLUTIONrerun1412003-12-19 11:05:16
Some Thoughtsthe possible combosrerun1412003-12-19 10:47:38
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