When I say "the first N digits of π", I mean counting the integer 3 but not counting the decimal point. For example, the first 5 digits of π are 31415.
Define the function pp2(N) as the N-th digit of π^2 where the first N digits of π are seen for the first time (after the decimal point).
So, pp2(1) = 13, because π^2 is approximately 9.869604401089358 and the first digit of pi, '3', first appears as the 13th digit after the decimal point.
Please find pp2(N) for N = 2,3,4,5.
