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Cube + Single Digit = Perfect Square (Posted on 2024-01-21) Difficulty: 3 of 5
Which is the highest cube n^3 < 108 that can be incremented by a single digit from 1 to 9 to yield a perfect square?

For example, 8 is a perfect cube. When incremented by 1 it becomes 81, which is a perfect square.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionComputer solutionLarry2024-01-21 13:21:12
Solutioncomputer solutionCharlie2024-01-21 12:39:47
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