All about
flooble

fun stuff

Get a free chatterbox

Free JavaScript

Avatars
perplexus
dot
info
Home
>
Numbers
Cubic Summation divisibility (
Posted on 20230713
)
For any positive integers n and m satisfying the equation n
^{3}
+(n+1)
^{3}
+(n+2)
^{3}
=m
^{3}
, prove that n+1 is divisible by 4.
No Solution Yet
Submitted by
Danish Ahmed Khan
No Rating
Comments: (
Back to comment list
 You must be logged in to post comments.
)
Solution
Comment 1 of 1
The only solution to the equation is 3^3+4^3+5^3=6^3
n+1=4 which is divisible by 4.
I didn't prove this, but it's not an uncommon question.
https://math.stackexchange.com/questions/120254/sumofthreeconsecutivecubes
Posted by
Jer
on 20230714 18:52:01
Please log in:
Login:
Password:
Remember me:
Sign up!

Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ

About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002  2024 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information