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 Logic of pets (Posted on 2023-08-21)
Robert and Andrew are two men, and Mary and Jessica are two women. Their last names are Jones, Smith, Coleman, and Thompson. One of them has a dog, one has a cat, one has a bird, and one has a rabbit. The pets are named Goody, Lovey, Lucky, and Weirdo.

1. Robert's pet's name starts with L.
2. Jessica Coleman has a cat, but it is not named Weirdo.
3. Mary does not have a dog because she hates dogs.
4. Lucky is a rabbit.
5. Mr. Jones has a bird.
6. Mary's last name is not Thompson.
7. Weirdo's last name is not Jones.

What is the first name and last name of each person? What pet does each person have? What is the name of each pet?

 No Solution Yet Submitted by Math Man Rating: 4.5000 (2 votes)

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 computer solution (spoiler) | Comment 1 of 5
people='ramj';
robert=1;
andrew=2;
mary=3;
jessica=4;
surnames='jsct';
pets='dcbr';
petnames='glLw';
surnames=perms(surnames);
pets=perms(pets);
petnames=perms(petnames);

for i=1:length(surnames)
surname=surnames(i,:);
for j=1:length(pets)
pet=pets(j,:);
for k=1:length(petnames)
petname=petnames(k,:);
good=true;
if lower(petname(robert))~='l'
good=false;
continue
end
if pet(jessica)~='c' ...
|| petname(jessica)=='w' ...
|| surname(jessica)~='c'
good=false;
continue
end
if pet(mary)=='d'
good=false;
continue
end
lucky=strfind(petname,'L');
if pet(lucky)~='r'
good=false;
continue
end
jones=strfind(surname,'j');
if pet(jones)~='b' || jones > 2
good=false;
continue
end
if surname(mary)=='t'
good=false;
continue
end
weirdo=strfind(petname,'w');
if surname(weirdo)=='j'
good=false;
continue
end
disp(people)
disp(surname)
disp(pet)
disp(petname)
disp(' ')
end
end
end

finds

`>> logicOfPetsramjjtscbdrclwLg`

Robert Jones has a bird named Lovey.
Andrew Thompson has a dog named Weirdo.
Mary Smith has a rabbit named Lucky.
Jessica Coleman has a cat named Goofy.

 Posted by Charlie on 2023-08-21 11:03:56

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