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Powers of Digits 2 (Posted on 2024-05-02) Difficulty: 3 of 5
Let N be a positive integer with an even number of decimal digits, say abcd...yz.

For how many N does a^b + c^d + ... + y^z? equal zy...dcba, that is, N with its digits reversed? One example is N=52, since 5^2 = 25.

[If 00 occurs, take its value as 1. Do not include any solutions ending with 00.]

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: GuestK Sengupta2024-05-09 21:26:14
re: GuestK Sengupta2024-05-09 21:25:40
GuestAnonymously2024-05-09 10:52:22
GuestAnonymously2024-05-09 10:51:47
SolutionComputer solutionLarry2024-05-02 13:12:34
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