There were 6 numbers of the same family.
One of them ran away.
Please catch it and prove it belongs to the original set.
The remaining five are:
 2,367,143
 5,713,643
 4,437,136
 3,433,671
 6,714,336
ENJOY!
The sums of digits are all different, from 26 to 30:
Perhaps the unknown number has sod() of either 25 or 31.
Steve Herman's number does have sod() = 25.
If the digits are 'unscrambled' into sorted order, we get:
1233467
1334567
1334467
1333467
1334667
The following 2 digit pairs occur in each:
43, 71, 36
also, they always appear in a different order, and always involving the last 6 digits, never the first digit.
The sum of these digits: 43, 71, 36 is 24.
For the final number, to have an sod() of 25 or 31, the missing digit must be either 1 or 7.
And the 3 pairs must be in a different order than the other 5 numbers.
It seems there could be two solutions:
Edited on September 25, 2023, 9:26 am

Posted by Larry
on 20230925 09:02:49 