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Fibonacci Thimbles (Posted on 2024-07-15) Difficulty: 3 of 5
One year, on Sue's birthday, Sue started a collection of thimbles. The following birthday she added to her collection, which went from strength to strength. In all subsequent years when she counted the thimbles on her birthday the total had increased from the previous year’s total by a number equal to the total she had on her birthday the year before that. (So, for example, her 1983 total equalled her 1982 total added to her 1981 total).

Now, by coincidence, her daughter was born on her birthday. And, with her collection growing following the described pattern, on their birthday in 1983 the number of thimbles Sue owned had reached exactly four times her daughter’s age on that day. On her birthday this year the total of thimbles was four times her age. On only one other occasion has the total been divisible by four, and that was in the year Sue's son was born.

How many thimbles were there in Sue's collection on her birthday this year? How many (if any) did she have the day her daughter was born?

No Solution Yet Submitted by K Sengupta    
Rating: 5.0000 (3 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
hi88gardenHi88 garden2024-08-07 20:44:37
Some ThoughtsPossible Solutionbroll2024-07-16 01:33:01
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