All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Triangle's features (Posted on 2024-01-15)
My right angled triangle has sides measuring n, n^2, n^3.

Evaluate its area, perimeter and centre of gravity.

 No Solution Yet Submitted by Ady TZIDON No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 Answer | Comment 2 of 5 |
n^2 + n^4 = n^6 a Golden equation
If t = n^2, t(t^2 - t - 1) = 0
t = (1 Â± âˆš5)/2 or phi
Since this is a triangle, negative and complex solutions are rejected
n^2 = (1 + âˆš5)/2 = 1.6180339887499

Trying to simplify by setting n = a + bâˆš5 leads to complex answers

n   = 1.27201964951407
n^2 = 1.6180339887499
n^3 = 2.05817102727149

If the triangle's vertices are at (0,0), (n,0), (0,n^2)
Area = 1.02908551363575
Perimeter = 4.94822466553546
Centroid:  (n/3, (n^2)/3)
(0.424006549838023, 0.539344662916632)
(I'm fairly sure the CG of an xyz right triangle is (x/3, y/3) from the right angle.)

 Posted by Larry on 2024-01-15 18:43:45

 Search: Search body:
Forums (2)