My right angled triangle has sides measuring n, n^2, n^3.
Evaluate its area, perimeter and centre of gravity.
Assuming that n^3 is the hypotenuse, we obtain:
n^2+n^4=n^6
=> n =~ 1.27201964951407
The area = (n*n^2)/2 =~ 1.02908551364
The perimeter = n+ n^2+n^3=~4.94822466554
The C.G. will be at: (n/3, n^2/3) = =~ (0.42400654983, 0.05992718476)
Assuming that n is the hypotenuse:
n^4+n^6=n^2
=> n =~ 0.786151377757423
The area = (n^2)*(n^3)/2 =~ 0.24293413587
The perimeter = n^2+n^3+n =~ 1.89005363826
The C.G. will be at: (n^2/3, n^3/3) =~(0.20601132958, 0.16195609058)
Edited on January 15, 2024, 11:20 pm
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