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Some Cubes Are 1 less than a Power of 3 (Posted on 2024-10-10) Difficulty: 3 of 5
Consider two positive integers x and y, and determine all possible pairs (x,y) that satisfy this equation:
x3 = 3y - 1

Provide valid reasoning for your answer.

No Solution Yet Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionAnswerMath Man2024-10-15 14:09:59
SolutionSolutionBrian Smith2024-10-10 12:13:01
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