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Shortest distance (
Posted on 20031210
)
What is the shortest distance between two opposite points (two vertices separated by 2R) in the surface of a regular icosahedron? The regular icosahedron's edges are 1ft in length.
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Submitted by
Antonio
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4.0000
(2 votes)
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Problem Solution
Comment 16 of 16 
The required shortest distance is 1*sqrt(7) = 2.645751 feet(appr0x.)
Posted by
K Sengupta
on 20070504 12:32:55
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