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Truncated Cube (Posted on 2004-03-04) Difficulty: 3 of 5
Suppose you truncate a cube such that this truncation of a vertex takes away 1/8 of the original area from each of 3 square faces and creates a new equilateral triangle. If you did this to all 8 vertices, what would the volume be? (Only use geometric formulas/reasoning for this problem.)

See The Solution Submitted by Gamer    
Rating: 3.6667 (3 votes)

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re: Solution | Comment 2 of 7 |
(In reply to Solution by Brian Smith)

Just a notational note.

The resulting figure is a cuboctahedron.
A truncated cube is usually considered the figure where the tetrahedra have edge length of less than half.

The exact length removed is 1-√(2)/2
this creates octagonal sides.

  Posted by Jer on 2004-03-04 12:25:16

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