A clock's minute hand has length 4 and its hour hand length 3.
What is the distance between the tips at the moment when it is increasing most rapidly?
I GOOFED ,
In my last post which provided a fast but totally
wrong answer I started with a false statement:
" If distance increases most rapidly so does its square...". SAYS WHO??
GIGO* - ALL THE REST IS WRONG.
(* GARBAGE IN --GARBAGE OUT)
My reasessment is as follows:
for A=.001 to 1.7
evaluate D=((25-24cos(A+.0001))^.5 D=distance
DD=((25-24cos(A+.0001))^ .5 DD=D increased
Checking the table for max. rate and refining the
search in the neigborhood-we get nice and round numbers:
max rate= 3
This corraborates Charlies solution, however without referring explicitly to calculus-just examining the deltas' (=inreases) ratio.
Edited on February 28, 2004, 9:02 am