A clock's minute hand has length 4 and its hour hand length 3.

What is the distance between the tips at the moment when it is increasing most rapidly?

I GOOFED ,

In my last post which provided a fast but totally

wrong answer I started with a false statement:

" If distance increases most rapidly so does its square...". SAYS WHO??

GIGO* - ALL THE REST IS WRONG.

(* GARBAGE IN --GARBAGE OUT)

My reasessment is as follows:

for A=.001 to 1.7

evaluate D=((25-24cos(A+.0001))^.5 D=distance

DD=((25-24cos(A+.0001))^ .5 DD=D increased

rate= (DD-D)/.0001

Checking the table for max. rate and refining the

search in the neigborhood-we get nice and round numbers:

max rate= 3

distance= sqrt(7)

cos(angle)=3/4

This corraborates Charlies solution, however without referring explicitly to calculus-just examining the deltas' (=inreases) ratio.

ady

*Edited on ***February 28, 2004, 9:02 am**