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A point in a square (Posted on 2004-03-17) Difficulty: 3 of 5
Given a square ABCD, let P be such that AP=1, BP=2 and CP=3.

* What is the length of DP?
* What is the angle APB?

See The Solution Submitted by Federico Kereki    
Rating: 3.1250 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Half a solution | Comment 1 of 7
Applying Pythagoras, AP squared plus CP squared must equal BP squared plus DP squared, so DP = √6.
  Posted by e.g. on 2004-03-17 14:54:52
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