Find a 3x3 magic square composed of distinct proper fractions with no denominator greater than 9.
Note: A proper fraction is a fraction between 0 and 1. A proper fraction is NOT equal to 0 or 1.
Am I missing something?
It seems one could take any integer magic square and divide all the terms by a constant.
Example:
6 7 2
1 5 9
8 3 4
divided by 11 becomes
6/11 7/11 2/11
1/11 5/11 9/11
8/11 3/11 4/11
A more challenging alternative might be all having different denominators when in lowest terms. Also smallest maximum denominator.
Jer

Posted by Jer
on 20040524 09:13:13 