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 Calendar Cubes (Posted on 2002-09-09)
A businessman has two cubes on his desk. Each cube has a number on each of its sides. Every day, the businessman arranges the cubes in such a way that the upward facing numbers display the day's date. (Note that both cubes are always used for this, so on the 7th of the month, the cubes' surfaces display "07".)

How are these cubes numbered? (I.E. What numbers are on which cube? - call them C1 and C2.)

 Submitted by levik Rating: 3.3750 (8 votes) Solution: (Hide) The trick to this problem is realising that by turning a "6" upside down, we can make a "9". Since there are only a maximum of 31 days in a month, we will never need a 6 and a 9 simultaneously. Because each month as an 11th and a 22nd, both the cubes will need to have the numbers 1 and 2 on them. Also, because each of the digits needs to appear next to a zero (for the first 9 days of the month), zero should also be on both cubes. This leaves us with three free spots on each cube, where we need to put the numbers 3, 4, 5, 6, 7, and 8. So, ``` C1 : 0, 1, 2, 3, 4, 5 C2 : 0, 1, 2, 6, 7, 8```

 Subject Author Date re(2): My Solution Dej Mar 2008-09-16 02:46:06 re: My Solution humfoozneydannle 2005-01-02 01:56:36 solution humfoozneydannle 2005-01-02 01:52:01 My Solution Wendy 2004-02-24 17:40:00 Neat Lawrence 2003-08-27 13:51:09 Reality Nick Reed 2002-09-13 07:07:40 re(3): Huh? levik 2002-09-10 10:12:31 re(2): Huh? friedlinguini 2002-09-10 05:09:43 re: Huh? levik 2002-09-10 04:52:21 upside down trick Dulanjana 2002-09-10 03:40:53 Huh? TomM 2002-09-10 03:05:02 13 digits TomM 2002-09-09 20:12:27

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