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Yet one more coin sorting problem (Posted on 2004-05-31) Difficulty: 3 of 5
You have five coins, apparently alike, but actually of different weights. You also have a two arm scale.

Can you manage to sort the coins in ascending order, using the scale only seven times?

Bonus question: can it be done in fewer weighings?

See The Solution Submitted by Federico Kereki    
Rating: 4.0000 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Full solution | Comment 15 of 20 |
(In reply to re: Full solution by Erik O.)

In e.g.'s method, you would have weighed the 3 vs the 4 and found the 4 heavier.  You would then have weighed the 1 vs the 2 and found the 2 heavier.  Then you would have weighed the 4 against the 2 and found the 4 heavier, so you'd know 4>2>1 and 4 > 3, so that the letters that would apply are d=4, b=2, a=1. (It's at this point that the labels are applied, and all the inequalities represent a weighed determination.)
  Posted by Charlie on 2004-06-02 13:48:58

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