All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers > Sequences
Explicitly Stated (Posted on 2004-08-18) Difficulty: 3 of 5
A certain bank doesn't believe in interest and gives none the whole year. However, they do two things as a gift at the end of the year. They put money into your account such that it has 5 times as much as it did before. Then, they put 8 dollars in the account after that.

Jack gets one of these accounts at the start of year 1, and puts in 6 dollars. Assuming there are no other withdrawals or deposits into that account, figure out how much money is in that account at the beginning of year x, even if you don't know how much was in the account any of the previous years.

For example, on the beginning of year 1, he would have 6 dollars. On the beginning of year 2, he would have 38 dollars, and on the beginning of year 3 he would have 198 dollars.

What if you put in A dollars to start at the beginning of the first year, the bank put money into your account at the end of the year such that it was B times as much as before, and then put in C more dollars after that; how much money would you have at the beginning of year x, assuming everything else is normal and there are no withdrawals or deposits, even if you don't know how much was in the account any of the previous years?

No Solution Yet Submitted by Gamer    
Rating: 4.0000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Another question: | Comment 5 of 11 |

By "Formula" I meant only exponents and basic operations, rather than algorithms (like the summation algorithm); I will make that "explicitly stated" in my future problems ;)

As for comments like the first comment, make sure your work is "explicitly stated" so we can follow where the formula came from.

Finally, another question: For the first "sample problem" (which nobody bothered to answer) the terms go 6, 38, 198, 998, 4998.... The differences between adjacent terms are 32, 160, 800, 4000; always a multiple of 32. Why are they multiples of 32 and (the more interesting question) how does that translate into A, B, and C in the second question in the problem?


  Posted by Gamer on 2004-08-18 15:30:53
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information