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 tic-tac-toe (Posted on 2004-07-30)
If I put nine pieces of paper, with a digit from 1-9 written on each one, into a hat, and pull 3 out without replacement, what is the likelihood that I will select three numbers that result in a winning tic-tac-toe?
``` 1 | 2 | 3
---+---+---
4 | 5 | 6
---+---+---
7 | 8 | 9 ```

 See The Solution Submitted by ThoughtProvoker Rating: 1.8333 (6 votes)

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 re: Answer | Comment 3 of 14 |

If the first number selected is a corner
the next number can be any 6 from 8, the final number can only be 1 from the remaining 7.

If the first number selected is a side
the next number can be any 4 from 8, the final number can only be 1 from 7.

If the middle number is selected first
the second number can be any. the final number can only be 1 from 7

Corner (4/9)x(6/8)x(1/7)=0.04761895.
Side (4/9)x(4/8)x(1/7)=0.03174996.
Middle (1/9)x(8/8)x(1/7)=0.01587301.

Add all the above probabilities together = 0.09524192

9.524192%

 Posted by Juggler on 2004-07-30 13:11:40

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