A six-shooter is loaded with three cartridges
in consecutive chambers, before two persons start to play "Russian Roulette" until one is dead.
If the cylinder isn't spun after each attempt, would you rather be the first shooter, or the second?
What would be your answer if there are only TWO cartridges, of course in consecutive chambers?
if you go first you have a 50/50 chance of living
if opponent goes first and lives then there are 3
live rounds and only 2 empties left anyone should
figure the odds now
by the way, I find this puzzle somewhat depressing,
do this stuff with heads or tails next time Fred, ok!
solution
