In a 8½x11 sheet of paper I drew two equal nonoverlapping circles  both completely inside the paper, of course.
What's the largest portion of the paper I could cover with the circles?
What would be the answer if I drew THREE equal circles?
(In reply to
re: Two circles casefurther explanation by Charlie)
I think I agree with putting the circles in opposite corners and then
expanding them until they are tangent to each other AND tangent to the
sides of the paper. Their centers being on 45 degree angles from
the corners, but their tangent point will not be on this same line, but
I guess we don't care. Working from center to center, we know:
(2r)^2 = (8.52r)^2 + (112r)^2
Here's were I don't follow. When I expand this, I get:
4r^2 = (8.5)^2  17r + 4r^2 + (11)^2  22r + 4r^2
4r^2 = 8r^2  39r + (8.5)^2 + (11)^2
0 = 4r^2  39r + (8.5)^2 + (11)^2, My question is where did your 78r term come from?
I would much rather have the 78, because when I plug my numbers into
the quadratic formula, I end up having to take the square root of a neg
number.

Posted by bob909
on 20041022 09:09:41 