All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Speaking Volumes (Posted on 2004-11-10) Difficulty: 3 of 5
In a group of students, 50 speak English, 50 speak French and 50 speak Spanish. Some students speak more than one language. Prove it is possible to divide the students into 5 groups (not necessarily equal), so that in each group 10 speak English, 10 speak French and 10 speak Spanish.

See The Solution Submitted by Brian Smith    
Rating: 3.1667 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Fairly simple solution (quick explanation) | Comment 18 of 19 |
First separate the students (as much as possible) into groups with exactly one student who speaks a particular language.

Then there must be an equal number of students who speak each pair of languages. (For example: AB AB AC AC BC BC) -- simply combine one of each type, (AB AC BC) and then put these smaller groups together to get large groups of 10 each, adding the other groups of one each as necessary.

The reason there must be an equal number of students who speak each pair of languages is because nothing else is possible -- it will either violate the assumption that we now still have the same number of students per language or the assumption that we have no combinations of students which form a group with exactly one student who speaks a particular language.

  Posted by Gamer on 2011-12-10 18:28:51
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (23)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information