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M&M (Posted on 2004-11-26) Difficulty: 3 of 5

What comes next in the following sequence?

1212210202001, 224000000, 11333311, 623351, 290221, ...?

See The Solution Submitted by Erik O.    
Rating: 2.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: solution, except that.. | Comment 2 of 4 |
(In reply to solution by Charlie)

I also noted that the sequence is 1,000,000 in different bases.  The tip off was the lack of large digits, and the greater number
of digits in the earlier members of the sequence.

But here's an excerpt from Charlie's print out:
"The representation of one million in odd bases, starting with 3 are:

3            1212210202001
5            224000000
7            11333311
9            1783661
11           623351
13           290221
15           14B46A
17           BG939"

Note that the base 9 version of 1 million does not 
appear in the sequence. So I believe there is
another sequence within the sequence,
that of the bases.
The bases used are 3,7,11,13.  So we need to figure 
the next base in the sequence; I think it is the sequence
of odd primes, so I think the next base is 17.
If true then the next number in the sequence is BG939.

 

Edited on November 26, 2004, 9:00 pm
  Posted by Larry on 2004-11-26 20:57:40

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