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M&M (Posted on 2004-11-26) Difficulty: 3 of 5

What comes next in the following sequence?

1212210202001, 224000000, 11333311, 623351, 290221, ...?

See The Solution Submitted by Erik O.    
Rating: 2.0000 (2 votes)

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Solution Puzzle Solution Comment 4 of 4 |

The nth term of the sequence is obtained by expressing the decimal number 1,000,000 in base P(n+1) where P(x) denotes the xth prime number.
Since, P(6) = 17; it follows that the missing term (fifth term) is obtained by expressing 1,000,000 in base 17; which is BG939.


  Posted by K Sengupta on 2007-03-11 12:53:23
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