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Who will win? (Posted on 2005-01-10) Difficulty: 4 of 5
There are 2n cards labeled 1, 2, ..., 2n respectively, and the cards are distributed randomly between two players so that each has n cards. Each player takes turns to place one card, and you win if you put down a card so that the current sum of all the played cards is divisible by 2n+1.

For example, if n=10, and the previously placed cards are 5, 8, 9, 19, then if player A now places 1, he wins since 5+8+9+19+1 = 42 is divisible by 2*10+1=21.

Assuming both players want to win, what strategy should one adopt in order to win? Following the strategy, is there a consistent winner of this game?

See The Solution Submitted by Bon    
Rating: 2.0000 (1 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: More thorough solutionJay Schamel2005-01-14 23:49:40
re(5): SolutionCharlie2005-01-10 20:12:13
More thorough solutionDavid Shin2005-01-10 19:50:27
re(4): SolutionDavid Shin2005-01-10 19:40:00
Questionre(3): SolutionCharlie2005-01-10 19:11:59
re(2): SolutionDavid Shin2005-01-10 18:52:43
SolutionPossible solutionHugo2005-01-10 18:11:17
Some Thoughtsre: Solutione.g.2005-01-10 18:07:22
SolutionSolutionDavid Shin2005-01-10 17:22:13
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