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Decagon (Posted on 2005-01-30) Difficulty: 4 of 5
There is a decagon with eight 150 degree angles and two 120 degree angles. The lengths of its sides are a set of ten consecutive integers. Maximize the length of its longest side.

See The Solution Submitted by Tristan    
Rating: 4.0000 (1 votes)

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Some Thoughts re: more thoughts | Comment 4 of 6 |
(In reply to more thoughts by Charlie)

Also, there cannot be two .5 multipliers and two sqrt(3)/2 multipliers on each side, as then for horizontal positioning, while the sum of the side lengths for the two .5 multipliers on each side would have to equal each other, the differences would also have to equal each other, making them the same pair of numbers.
  Posted by Charlie on 2005-01-31 00:28:25

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