I am holding a collection of items in my hands.
I throw two of the items away.
I want to divide it into different groups, but I can only see one half of each item in my hands.
I can easily divide the items into the same amount of groups:
as there are day and night.
as there are seasons.
as there are lunar months.
as there are weeks in the year.
If I add up all the values together,
I get the amount of days in a year
(minus 1 for the two items I threw away.)
What do I have?
(In reply to
Puzzle Answer by K Sengupta)
The puzzle author has "a deck of cards"
Take out the 2 jokers. Then, the division of the items (deck of cards) into the specified number of groups is explained as:
As there are:
i) Day and night => Black and Red cards
ii) 4 seasons => 4 Suits
iii) 13 lunar months =-> 13 values, which are: A,2,3,4,5,6,7,8,9,J,Q, K
iv) 52 weeks in a year => 52 cards in total in 4 suits each having 13 values.
Now, we assign the following numeric values to the "valued cards":
A=1, |2,3, 4, 5 6, 7, 8, 9, 10| , J= 11, Q= 12, K= 13
Adding the 13 distinct values we have:
1+2+...+13 = (13*14)/2 = 91
Therefore, the total values in the 4 suits add up to 91*4=364 which is precisely 1 less than the number of days in a year.
Edited on May 14, 2022, 11:23 pm
Explanation to Puzzle Answer
