1. At least 1 statement among these 2n+1 are true.
2. At least 3 statements among these 2n+1 are false.
3. At least 5 statements among these 2n+1 are true.
...
2n. At least (4n1) statments among these 2n+1 are false.
2n+1. At least (4n+1) statements among these 2n+1 are true.
How many statements are true? Which?
In a quick approach:
Statements from n+1 from 2n + 1 are always false (not logic).
Statement n is always false (with n even or odd).
Statement 1 to n1 are some true and some false:
They are false when states to be true a number of statements superior to n1, so: odd terms (statements) higher than n/2 and inferior or equal to n1 are also false.
So, the number of false statements is superior to
(n + 1) + 1 + (n2)/4 (is > than (5n + 6)/4 con n even).
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NB: Last part was needed of some correction, so I've changed the original = in >, and the problem hasn't been solved (but I can't do it now).
Edited on June 13, 2005, 3:38 pm
Edited on June 13, 2005, 4:50 pm

Posted by armando
on 20050613 14:59:09 