Find the rule and continue this sequence of digits:
1235813941213533488671216141383377554...
Is there a limit to the number of times in a row a digit can appear?
(In reply to
re: Theoretically (growing vs. shrinking patterns) by Charlie)
As Charlie points out, there is a string of 9 1's at location 20560, therefore there will be a string of 27 1's sometime later.
Based on the pattern shown in an earlier response, I am led to conclude that there is no limit to the number of times the digits 1, 2, 4, 5, 7, and 8 can occur in a row.
What about 0, 3, 6, and 9?
4 3's makes 3 3's:
3333
666
1212
333
5 3's makes 5 3's:
33333
6666
121212
33333
and 6 3's gives 7 3's:
333333
66666
12121212
3333333
So if 6 or more 3's appear together there is no limit to the number of 3's or 6's.
3 9's make 3 more 9's and 4 9's make 5 9's:
9999
181818
99999
6 3's appear together in Charlie's latest listing, and 4 9's appear together so the only digit with a limit is the digit 0.
Any number (n) of 0's together creates (n1) 0's, so to get an unlimited number of 0's together you would have to start with an an infinite number. There are no 2 digit combinations that create 2 or more 0's together.

Posted by Erik O.
on 20050628 20:56:58 