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Pair Playing Probability (Posted on 2005-08-02) Difficulty: 3 of 5
There are N players in a tennis tournament. Assuming the initial pairings are done randomly, what are the odds that a certain pair will play each other?

See The Solution Submitted by Old Original Oskar!    
Rating: 3.0000 (2 votes)

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re: I undestood right? | Comment 2 of 31 |
(In reply to I undestood right? by pcbouhid)

If this were the correct interpretation of the problem, the answer given is still not right, as there are N/2 pairings actually taking place in the first round (or (N-1)/2 if N is odd).  That increases the chances by this factor, making the overall probability (N/2)/C(N,2) or ((N-1)/2)/C(N,2).

More likely though, the interpretation should be as to whether the two will play each other eventually during the tournament at some round or other.

Edited on August 2, 2005, 3:59 pm
  Posted by Charlie on 2005-08-02 15:11:25

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