In the classic problem you are given a triangle ABC with points D on AB, E on BC, and F on AC such that AD=2DB, BE=2EC, and CF=2FA. The lines AE, BF, and CD enclose a triangle inside triangle ABC. You are to find the area of this enclosed triangle relative to that of ABC. The answer is 1/7.
What if everything is the same except BE=EC and CF=3FA. What is the area of the enclosed triangle relative to that of ABC?
(In reply to
re: According to Geometer's Sketchpad... (spoiler) by McWorter)
Yes, it should be 1/10, as I was taking the ratio the wrong way around.

Posted by Charlie
on 20050823 20:22:30 