The judge´s wife (Posted on 2005-12-08)

     A-1   B-2   C-3   D-4   E-5   F-6   G-7   H-8   I-9
     J-10  K-11  L-12  M-13  N-14  O-15  P-16  Q-17  R-18
     S-19  T-20  U-21  V-22  W-23  X-24  Y-25  Z-26

	Submitted by pcbouhid
Rating: 4.1667 (6 votes)
Solution:	(Hide)
From (1), the name of the judge´s wife has a "product" of 10 x 21 x 4 x 7 x 5. From (2), her name has no G(7) or U(21); so it has N(14) twice. Division by 14 twice leaves 10 x 3 x 5. From (2), her name has no E(5) or J(10). It cannot have a T(20). It cannot have an O(15); otherwise, it would have an E(5) or a J(10). So her name has a Y(25). Division by 25 leaves 2 x 3. From (3), her name has an F(6). Division by 6 leaves 1. In alphabetical order the letters found so far are FNNY, and the only other letter her name may contain is A(1). So from 4, the name of the judge´s wife is FANNY. Note: The "W" in Edwin is the twenty-third letter of the alphabet and can only be represented as 23 x 1. So to find a woman whose name satisfied the first two conditions in relation to EDWIN is impossible.

	Subject	Author	Date
	Answer	K Sengupta	2008-03-19 11:02:11
	Good one..	Jessica	2006-01-19 18:32:27
	answer	nick	2005-12-12 17:40:02
	re(3): Solution	MindRod	2005-12-09 17:46:43
	re(2): Solution	pcbouhid	2005-12-09 13:35:15
	re: Solution	MindRod	2005-12-09 11:03:27
	Solution	Lukahn	2005-12-09 02:23:20
	Judge's Wife	Danyel	2005-12-08 14:25:08
	Answer (Spoiler)	Vernon Lewis	2005-12-08 14:02:28
	Spoiler - answer and raising the flag	Leming	2005-12-08 08:53:52