If a, b, and c are different numerals between 1 and 9 (inclusive), and
aaaaaa = b * c * bc * (c+c-b) * (c+b+b) * (c-b),
what are a, b, and c?
Note: Adjacent numerals are multi-digit numbers made of those numerals, not the product; i.e., if m=2 and n=3, then mn=23.
aaaaaa = a*(111111)
fits nicely into b * c * bc * (c+c-b) * (c+b+b) * (c-b)
only thing missing is c-b which is a. Therefore a = 4.
Posted by rohit
on 2005-09-27 08:09:59