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Another Man's Floor (Posted on 2005-11-23) Difficulty: 4 of 5
Let a, b, and m be positive whole numbers. Required is a fast algorithm for evaluating Σk=0..m floor(ka/b), floor(x) being the greatest integer that does not exceed the real number x.

See The Solution Submitted by Richard    
Rating: 4.5000 (2 votes)

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Some Thoughts A simplification | Comment 1 of 11
If a>b, we can write a=bn+c, and then we are summing terms like k.(bn+c)/b= kn+kc/b.

The first term is an integer, so we can take it out of the floor function, and we sum kn for k=0 to m, which equals km(m+1)/2.

The second term is the tougher part, but now we can solve it for c<b... or cannot we?
  Posted by e.g. on 2005-11-23 13:14:53
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